Divide 360 by 2 three times to reach 45, divide by 3 twice to reach 5, then keep the final prime 5. Grouping yields 2^3 × 3^2 × 5.
Multiply back to 360
Eight times nine times five equals 360, so the exponent form recomposes the input exactly.
Why the divisions stop at 5
After removing every factor of 2 and 3, the remaining quotient is 5. Because 5 is prime, it cannot be split into smaller integer factors other than 1 and itself. That final remainder therefore contributes one factor of 5 and completes the unique prime factorization.
Reproduce the complete example
Open the calculator, enter the exact integer shown in the example, and compare both the exponent form and expanded factors. Multiply every expanded factor; the product must equal the normalized input exactly.